Understanding Source Transformations in Operational Amplifier Circuits

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
8 replies · 2K views · last reply
dwn
Messages
165
Reaction score
2

Homework Statement


See Image

Homework Equations



Source Transformations

The Attempt at a Solution



The answer is given, but I do not understand how they got it. When I multiply 9mA and 947.308Ω resistor, I get 8.526...what am I doing wrong? Also, could someone explain how they went on to get the final voltage in the simplified circuit. Don't you just add voltages when they are in series like this...?
 
Attachments
  • Circuit schematic of an op-amp circuit with a 9 mA current source in parallel with 1 kΩ and 9 kΩ resistors, a 5.4V source and 510Ω resistor on the non-inverting input, and 740Ω and 150kΩ feedback resistors, output labeled V2; text reads Step 1 about source transformation.
    Screen Shot 2014-03-29 at 6.24.37 PM.jpg
    20.2 KB · Views: 577
  • Op-amp circuit schematic: 13.92V voltage source with 1.457kΩ series resistor into the inverting input, 740Ω feedback resistor from output to inverting input, 150kΩ resistor to output node labeled V2, non-inverting input grounded.
    Screen Shot 2014-03-29 at 6.36.27 PM.jpg
    4.9 KB · Views: 546
Physics news on Phys.org
What does the Rf represent as well?
 
Attachments
  • Equation for an inverting amplifier gain: -Rf/R1 = -150.74k / 1.457k = -103.459, with the numerator and result in red.
    Screen Shot 2014-03-29 at 7.06.46 PM.jpg
    4.3 KB · Views: 538
9 x 0.947 = 0.947 is obviously wrong, and looks like a typo.
It should be 9 x 0.947 = 8.523.
 
I haven't built up a lot of confidence with circuit analysis, so I wanted to make sure that it was in fact an error on there part. Thanks guys.
 
dwn said:
According to their calculation they got .947 V

For what? We need some context here.

dwn said:
What does the Rf represent as well?

Rf is the resistance in the op-amp feedback path.
 
dwn said:
What does the Rf represent as well?

The feedback resistor. 150k + 0.740k in series.
 
gneill said:
For what? We need some context here.

This is an online homework site and the guided solution provided a step-by-step solution, which is pictured in the first image I attached. AlphaZero already answered my question.

Thank you for the help.