Opposing Forces on an Ideal Spring

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SUMMARY

The discussion centers on the dynamics of an ideal massless spring subjected to unequal forces. It establishes that a massless spring cannot overshoot its uncompressed length due to the conservation of energy principles. When compressed and released, the spring oscillates with an amplitude defined by the difference in lengths, and its angular frequency is determined by the formula sqrt(k/m). As mass approaches zero, the spring's angular frequency increases, allowing it to overshoot its uncompressed length, with energy transitioning between potential and kinetic forms throughout the oscillation.

PREREQUISITES
  • Understanding of Hooke's Law and spring dynamics
  • Familiarity with concepts of potential and kinetic energy
  • Knowledge of angular frequency and oscillatory motion
  • Basic calculus for limits and derivatives
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  • Study the derivation of angular frequency in oscillatory systems
  • Explore energy conservation in mechanical systems
  • Investigate the effects of mass distribution on spring dynamics
  • Learn about real-world applications of springs in engineering
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Physics students, mechanical engineers, and anyone interested in the principles of oscillatory motion and energy conservation in spring systems.

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can we exert 2 unequal forces in opposite directions on the two sides of an ideal<mass less> spring?
 
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can u tell me some more facts abt springs..how to solve problems involving springs with mass and without mass..??
 
A massless spring is compressed then suddenly released. Does it overshoot its uncompressed length? Where does the stored energy go?
 
YorkLarry said:
A massless spring is compressed then suddenly released. Does it overshoot its uncompressed length? Where does the stored energy go?

It can not overshoot its uncompressed length,because it's not accord with conversation of energy. when you release the massless spring,the stored energy switch the spring's kinetic energy,or else why the spring can kinetic without energy
 
I did some calculations after the last post. I've never seen an actual massless spring, and I don't know how to make one or where to buy one, so I added some mass m by gluing a mass m/2 to each end of the spring. I worked out the dynamics and then took the limit as m approaches zero.

If the spring with relaxed length Lo is compressed to length L1 and then released, it will oscillate with amplitude (Lo - L1) independent of m. It has angular frequency sqrt(k/m). The potential and kinetic energy exchange during the motion so as to keep the total energy constant. The maximum kinetic energy equals the maximum potential energy.

As the limit of small m is approached, the angular frequency increases, and the ends of the spring move faster and faster. So the spring will overshoot its uncompressed length regardless of how small m is. The stored energy goes into kinetic energy during the motion, except at the extremes of spring length.

If the mass m is distributed along the length of the spring instead of being concentrated at the ends, the argument is the same. Slices of mass other than at the ends move more slowly than the ends so the kinetic energy formulas are slightly different. The amplitude is still Lo - L1. The angular frequency is still proportional to sqrt(k/m) with the proportionality constant dependent on details of the mass distribution. Behavior in the massless limit is the same.

I can provide details if anyone is interested.
 
Apologies re the previous post - the angular frequency should be 2 sqrt(k/m). I dropped the factor of two.
 

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