Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Optical modulation transfer function of an image and its cutoff

  1. Aug 28, 2012 #1
    I have an image taken with a camera. I know the f/#, focal length, CCD characteristics, and an approximate distance to my scene. I computed the modulation transfer function but I am trying to map the pixel space to cy/m and having trouble. I essentially want to determine the cutoff spatial frequency. Any tips on how to do this?
     
  2. jcsd
  3. Aug 28, 2012 #2
    The limitation on the spatial frequency will be set either by the diffraction limit of the lens (see the Raleigh criterion) or by the Nyquist frequency of the sensor. You should be able to compute those given the data you have.
     
  4. Aug 29, 2012 #3
    My image is 1024x1024 and after computing the MTF, integrating it about theta from 0 to 2pi, I have a plot from 0 to 512 in pixels on my x-axis. I think I divide my pixel value by my ccd pixel size and that will have my x-axis in cy/m. Am I thinking of that correctly?
     
  5. Aug 29, 2012 #4
    I don't understand what you are trying to accomplish. I understand what spatial frequency and cutoff spatial frequency are, but "mapping pixel space to cy/m" means nothing to me.
     
  6. Aug 29, 2012 #5
    Just converting the x-axis from pixels to cylces/m
     
  7. Aug 29, 2012 #6
    The x-axis is the spatial frequency, correct? Then how come it is in pixels? Did you mean cycles/pixel?
     
  8. Aug 29, 2012 #7
    yes, yes
     
  9. Aug 29, 2012 #8

    Andy Resnick

    User Avatar
    Science Advisor
    Education Advisor
    2016 Award

    You can calculate the cutoff frequency directly (assuming diffraction-limited performance, etc.) with the information you already have- the entrance pupil diameter 'd' is given by the focal length and f/#, and the cutoff frequency for coherent imaging is f_c = d/(2*λ*f), where λ is the wavelength and f the focal length of the lens. For incoherent imaging, the cutoff frequency is twice that of coherent imaging.

    Measuring the OTF directly from an image requires some care, but is straightforward. The procedure I use is to image a sharp edge (a sharp black-to-white transition) and differentiate the image to obtain the line spread function. The OTF (in one direction) is the Fourier transform of the LSF, but the specific frequency values (in 1/pixels) will scale with how many image pixels you used. Correct for that, and then knowing the pixel size, you can obtain the OTF in image space (in, for example, cycles/mm). If you then want the OTF in object space ('resolution limits'), you need to know the magnification of the lens.

    Does this help?
     
  10. Aug 29, 2012 #9
    Yes, thank you
     
  11. Aug 30, 2012 #10
    Presumably that only works if your OTF dominates over the effects of the pixel size, otherwise you'll be making a non-stationary measurement of the pixel transfer function.

    To get the true pre-sampling OTF you need to tilt the edge and interpolate.
     
  12. Aug 30, 2012 #11

    Andy Resnick

    User Avatar
    Science Advisor
    Education Advisor
    2016 Award

    To be sure, there are a lot of subtleties I glossed over- the point spread function may vary over the field of view, there may be aliasing due to the spatial frequencies of the sampling, etc. etc.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Optical modulation transfer function of an image and its cutoff
Loading...