Optics Equations - to reduce height

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Is there an optics equation that can take an existing optics set-up and tell you would components, you would need to reduce the distance and still get the same result?

I have a working system, but it is really larger and I would like to reduce the distance, the height.
I am using a light source to pre-analyzer filter to lens to camera, a basic Optical setup.

Is that any equation I can use ?
 
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I want to reduce the distance from the camas to the lens and keep my same focus.
 
btb4198 said:
I want to reduce the distance from the camas to the lens and keep my same focus.
That still doesn't mean a lot to me, I'm afraid. You may know what you mean but you are leaving out a lot of stuff that's necessary for me to understand you.

I presume you know the simple lens equation (1/u +1/v = 1/f) and the ratio of image and object size being equal to the two distances. Have you read around about this or is this your first taste of optics? It isn't clear.
 
Reducing the diameter and spacing of the elements without changing their power will do nothing but make your image worse. Optical systems are notoriously difficult to optimize, so I'm not sure there's a simple equation that would work. Unfortunately my 2 semesters of optics didn't give me enough knowledge to elaborate further or give a concrete answer.
 
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Drakkith said:
Reducing the diameter and spacing of the elements without changing their power will do nothing but make your image worse
Whilst this is sometimes the case, most camera lenses sit between diffraction and aberration problems. For a lot of photography, diffraction is not a problem and f values around f8 will give least impairment. f1.4 is a great advantage for low light or movement but not a 'preferred value' when a smaller stop will work.

The OP is far too vague for a good answer, as I have already said. If the requirement is very critical then any suitable (obviously multi-element) lens would be optimised for its size and you'd have to pay for it!

Some input from OP is required now.