Optics finding index of refraction

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SUMMARY

The discussion focuses on determining the refractive index of a transparent glass plate using a microscope. The key data includes a barrel position change of 1.87mm and a plate thickness of 1.5mm. The relevant equation for this calculation is nglass/nair = y/y', where nglass represents the refractive index of the glass and nair is the refractive index of air. The second image observed is due to the refraction of light as it passes through the glass, causing a shift in the focal point.

PREREQUISITES
  • Understanding of optics principles, particularly refraction.
  • Familiarity with the concept of refractive index.
  • Basic knowledge of microscope operation and measurements.
  • Ability to manipulate and apply equations related to optics.
NEXT STEPS
  • Study the derivation and application of the equation nglass/nair = y/y' in optics.
  • Research the principles of light refraction and its effects on image formation.
  • Learn about the use of microscopes in optical measurements and experiments.
  • Explore practical examples of calculating refractive indices in various materials.
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Students in physics or optics courses, educators teaching optics concepts, and anyone involved in experimental physics or optical measurements.

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Homework Statement



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In order to determine the refractive index of a transparent plate of glass, a microscope is first focussed on a tiny scratch on the upper surface and the barrel position is recorded. Upon further lowering the microscope barrel by 1.87mm , a focussed image of the scratch is seen again. The plate thickness is 1.5mm. What is the reason for the second image and what is the refractive index of the glass?

Homework Equations



nglass/nair = y/y'

The Attempt at a Solution



i know the reason for the second image, my problem is I'm not sure what to do with the data given, because all that I've tried my answers are too high or to low. I'm also not sure if that equation is relevant, or what to use. I've read my text a few times, and i see nothing that even relates to this problem.
 
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does anyone have an idea?
 

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