- #1
The_Foetus
- 3
- 0
Hi,
Recently I did an experiment to try and discover what some objects look like microscopically, using a laser and looking at their diffraction patterns. We used the fact that the intensity profile you obtain is the Fourier transform of the object you're shining it through, so we can recover what the original object looks like by taking the Fourier transform of the image.
However looking back over it, I'm getting very confused about the mathematics converting the distances in our Fourier transform to real distances.
We used a camera and MATLAB to do the Fourier transform, and we got a conversion of about 50 pixels/mm for the camera. The difficulty comes when using the co-ordinates in matlab. For instance, for one of our objects, when we took the Fourier transform it returned that the co-ordinate distance between peaks was 100 pixels (or 1/pixels?). We used k = (2pi/λf)x, but do we get the real distance between peaks to be 100*(λf/2pi) or what? Apologies if this sounds a bit confusing, will try and compose my sentences better if it's too unclear
Recently I did an experiment to try and discover what some objects look like microscopically, using a laser and looking at their diffraction patterns. We used the fact that the intensity profile you obtain is the Fourier transform of the object you're shining it through, so we can recover what the original object looks like by taking the Fourier transform of the image.
However looking back over it, I'm getting very confused about the mathematics converting the distances in our Fourier transform to real distances.
We used a camera and MATLAB to do the Fourier transform, and we got a conversion of about 50 pixels/mm for the camera. The difficulty comes when using the co-ordinates in matlab. For instance, for one of our objects, when we took the Fourier transform it returned that the co-ordinate distance between peaks was 100 pixels (or 1/pixels?). We used k = (2pi/λf)x, but do we get the real distance between peaks to be 100*(λf/2pi) or what? Apologies if this sounds a bit confusing, will try and compose my sentences better if it's too unclear