Discussion Overview
The discussion revolves around determining whether a spectral peak at 100 MHz can be resolved given a wavelength resolution of Δλ 0.5 nm. Participants explore the relationship between frequency and wavelength in the context of optics and resolution, focusing on the implications of the full width at half maximum (FWHM) and the medium in which the measurements are taken.
Discussion Character
- Technical explanation
- Mathematical reasoning
- Debate/contested
Main Points Raised
- One participant questions whether the 100 MHz refers to the peak frequency or the FWHM, seeking clarification on the mean wavelength.
- Another participant confirms that 100 MHz is indeed the FWHM and specifies that the mean wavelength is approximately 500 nm.
- A suggestion is made to convert the FWHM into a wavelength range by first converting the mean wavelength to frequency, adjusting for the FWHM, and then converting back to wavelengths to compare with the spectrometer's resolution.
- It is proposed that the ratio Δf/f should be compared with Δλ/λ to determine if the peak can be resolved, with Δf representing the FWHM and Δλ the spectrometer resolution.
- A participant raises a concern about the validity of the ratio Δf/f = λ·Δf/c in non-vacuum conditions, prompting a discussion about the medium of operation for the spectrometer.
- Clarification is provided that the speed of light in a medium is given by c/n, where n is the refractive index, affecting the relationship between wavelength and frequency.
Areas of Agreement / Disagreement
Participants express differing views on the implications of the medium for the calculations and the validity of certain approximations, indicating that the discussion remains unresolved regarding the best approach to determine peak visibility.
Contextual Notes
There are limitations regarding the assumptions made about the medium's effect on light speed and the applicability of certain formulas in different conditions. The discussion does not resolve these issues.