# Optimization and related rates trig.

1. Nov 19, 2009

### amcelroy13

1. The problem statement, all variables and given/known data

A woman at point A on the shore of a circular lake with radius 2 miles wants to arrive at point C diametrically opposite A on the shore of the lake in the shortest time possible. She can walk at 4 mph and row a boat at 2 mph. To what point on the shore of the lake should she row before walking o minimize time? Verify your answer.

2. Relevant equations

Distance = velocity x time
t=d/v
total time = d in water/2mph + d on land/4mph

3. The attempt at a solution

I know that I must use angles to find the point B but I have no idea exactly what to do. If i could find the relation I could easily optimize it, but I really have no idea how to do it.

2. Nov 19, 2009

### LCKurtz

Your equation: total time = d in water/2mph + d on land/4mph is a good start. Draw a picture showing the person traveling a little way around the circumference to a point B. Call the center of the lake O. Call angle ACB $\theta$ and notice that angle AOB is $2\theta$. You should be able to get the walking distance arc AB and the rowing distance BC in terms of $\theta$ to put in your equation for time. Then you are on your way.

3. Nov 19, 2009

### amcelroy13

so if arc AB = r*2theta (i think) would BC = 2/sin(pi-2theta)?

4. Nov 19, 2009

### amcelroy13

never mind, that was dumb, its not a right triangle, BC would be r*(pi-2theta)

5. Nov 19, 2009

### amcelroy13

as of now i have gotten:

time=((r(pi-2theta)/2)+r*2theta/4
r=2 so i have:
time = pi-(pi*theta)+2pi
I have no idea how to optimize... any help?

6. Nov 20, 2009

### LCKurtz

You don't have the equation for BC correct. You are going to need some trig functions. In your figure, drop a line from B perpendicular to the diameter AC and call the intersection P. Now CBP is a right triangle and the rowing part BC is its hypotenuse. You can get OP from the little triangle OPB with a trig function and CP = OP + r. Now you can get the rowing distance CB from triangle CPB with another trig function. You have the walking arc length correct.

7. Nov 20, 2009

### amcelroy13

I figured it out, thanks for the help

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