Optimization semicircle problem

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SUMMARY

The optimization problem regarding the area of a Norman window, which consists of a semicircle atop a rectangle with a total perimeter of 28 feet, has been solved. The area function is defined as A(b) = 14b - (4 + π/8)b². The critical point for maximizing the area is found by setting the derivative A'(b) = 14 - (4 + π/4)b to zero, leading to the optimal width b = 56/(4 + π). The maximum area calculated is approximately 54.8897 square feet, confirming that the initial setup was correct, but rounding errors affected earlier results.

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[SOLVED] Optimization problem

Homework Statement



A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the smicircle is equal to the width of the rectangle. What is the area of the largest possible Norman window with a perimeter of 28 feet?

Homework Equations




After solving for b and plugging b into the Area formula I cannot determine the local max. Is the algebra or derivative wrong?

The Attempt at a Solution

please see attachment
 

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Thanks for your suggestion, the perimeter of a circle is also also pi*diameter, so then a semi-circle P=1/2pi*d. Which is what I have for the 1st equation
 
jimen113 said:

Homework Statement



A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the smicircle is equal to the width of the rectangle. What is the area of the largest possible Norman window with a perimeter of 28 feet?

Homework Equations




After solving for b and plugging b into the Area formula I cannot determine the local max. Is the algebra or derivative wrong?

The Attempt at a Solution

please see attachment

Solution:
A(x)=14b-(4+pi/8)*b^2
A'(x)=14-(4+pi/4)*b
Solve for b: (56/4+pi)
Insert b into the original area formula A(x) and the area of the largest possible window=54.8897ft
The problem was set up correctly except that I rounded off to only one significant figure and that's why my original answer didn't match the answer provided in the book.
 

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