SUMMARY
The smallest value of \( n \) for which \( \frac{n! \cdot n!}{(n+6)!} \) is an integer is determined through factorial simplification. The expression simplifies to \( \frac{1}{(n+1)(n+2)(n+3)(n+4)(n+5)(n+6)} \). Therefore, \( n \) must be at least 0 to ensure the denominator does not introduce any non-integer values. The confirmed smallest integer solution is \( n = 0 \).
PREREQUISITES
- Understanding of factorial notation and properties
- Basic knowledge of integer solutions in mathematical expressions
- Familiarity with simplification of algebraic fractions
- Concept of divisibility in number theory
NEXT STEPS
- Explore factorial properties in combinatorics
- Study integer solutions in algebraic expressions
- Investigate the role of divisibility in number theory
- Learn about simplification techniques for algebraic fractions
USEFUL FOR
Mathematicians, students studying combinatorics, and anyone interested in number theory and algebraic expressions.