Optimizing Paraboloid Bounds for Triple Integral

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SUMMARY

The discussion focuses on evaluating the triple integral of the function \(x\) over the solid bounded by the paraboloid defined by \(x = 2y^2 + 2z^2\) and the plane \(x = 2\). The participant provided bounds for the variables \(z\), \(y\), and \(x\) as follows: for \(z\), \(-\sqrt{1-y^2} \leq z \leq \sqrt{1-y^2}\); for \(y\), \(-1 \leq y \leq 1\); and for \(x\), \(2y^2 + 2z^2 \leq x \leq 2\). The bounds were confirmed to be correct, and the integral setup was clarified to ensure proper evaluation of the triple integral.

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Homework Statement


Evaluate the triple integral xdV where E is the solid bounded by the paraboloid x= 2y^2 + 2z^2 and x=2.

The Attempt at a Solution


The bounds I got are

for z

-sqrt(1-y^2) <= y <= sqrt(1-y^2)

for y

-1 <= y <= 1

for x

2y^2 + 2z^2 <= x <= 2

are these correct?
 
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[tex]\iiint{2y^2+2z^2\leq x\leq 2}xdV= \iint_{y^2+z^2\leq 1}\int_{2y^2+2z^2}^{2}x\,dxdA[/tex]
 
Im sorry I don't quite understand what you have written, can you please explain if possible?
 

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