Orbital angular momentum possible values of an electron in a hydrogen atom

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SUMMARY

The possible values of orbital angular momentum for an electron in a hydrogen atom with a principal quantum number n = 3 are derived from the quantum number l, which can take values of 0, 1, and 2. Using the formula L = √(l(l+1))ħ, the corresponding angular momentum values are 0, √2ħ, and √6ħ. This conclusion confirms the correct application of quantum mechanics principles to determine angular momentum in atomic systems.

PREREQUISITES
  • Understanding of quantum numbers in atomic physics
  • Familiarity with the formula for orbital angular momentum L = √(l(l+1))ħ
  • Basic knowledge of hydrogen atom structure
  • Concept of principal quantum number (n)
NEXT STEPS
  • Study the implications of quantum numbers on electron configurations
  • Explore the relationship between angular momentum and magnetic quantum number
  • Learn about the significance of quantum mechanics in atomic theory
  • Investigate the role of angular momentum in spectroscopy
USEFUL FOR

Students of quantum mechanics, physics educators, and anyone studying atomic structure and electron behavior in hydrogen atoms.

Ezequiel
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Homework Statement



What are the orbital angular momentum possible values for an electron in a hydrogen atom with a principal quantum number n = 3?

Homework Equations



L = \sqrt{l(l+1)}\hbar

The Attempt at a Solution



Possible values for l are 0, 1, 2.

So, substituting these in the equation above I get: 0, √2\hbar, √6\hbar.

Is this the right answer?
 
Physics news on Phys.org
yep, that looks right.
 
Thank you again :)
 

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