Orbital period and speed of a space shuttle in flight

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SUMMARY

The orbital speed of the space shuttle in a 290-mile-high orbit is calculated using the formula v=√(GM/(R+h)). With the Earth’s mass (Me) at 5.98x10^24 kg and the gravitational constant (G) at 6.67x10^-11 N m²/kg², the shuttle's speed is determined to be approximately 7639.54 m/s. The calculations also yield an orbital period (T) of 5622.8 seconds. The initial attempt at solving the problem involved incorrect values and assumptions, which were clarified through subsequent calculations.

PREREQUISITES
  • Understanding of gravitational physics and orbital mechanics
  • Familiarity with the formula v=√(GM/(R+h))
  • Knowledge of the Earth's mass and radius
  • Basic algebra and unit conversions (miles to meters)
NEXT STEPS
  • Study the derivation of orbital mechanics equations
  • Learn about the implications of varying orbital altitudes on speed
  • Explore the effects of gravitational forces on satellite motion
  • Investigate real-world applications of orbital speed calculations in aerospace engineering
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Aerospace engineers, physics students, and anyone interested in understanding the dynamics of satellite motion and orbital mechanics.

kevnm67
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Homework Statement


The space shuttle is in a 290-mile-high orbit. What is the shuttles orbital speed?


Homework Equations


v=√GM/R+h


The Attempt at a Solution


Period:
Me= 5.98x10^24kg
Re= 6.38x10^6m
H= 290miles * 1609m = 466610m

v= √(6.67x10^-11 N)(5.98x10^24 kg)/ (6.38x10^6 m)+ 466610 m

I didn't get the correct answer and would like some help working through this problem.
 
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v = \sqrt {\frac{ G M } {R+h}}
 
That's the equation I used above
 
i don't know if this is correct but here are my recent calculations:

v=2pi r/T ---> 42955687.5/T
G*M/r^2 = 8.5368*r= 58362553.54 ->v=sqrt(58362553.54)= 7639.54
T=2pi r/v = 5622.8
 

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