Orbital Radius of Earth Satellite: Solve for r

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SUMMARY

The discussion focuses on calculating the orbital radius of an Earth satellite in a circular orbit with a period of 1 day. The formula used is r^3 = (GMT^2) / (4(pi)^2), where G is the gravitational constant, M is the mass of the Earth, and T is the orbital period. The user, Bernie, initially calculated the radius as 21642 km but realized the error was due to not converting the period T into seconds. The correct orbital radius, as stated in the reference book, is 42.2 Mm (megometers).

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Bernie Hunt
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Find the orbit radius of an Earth satellite in a circular orbit if the period if 1d.

I'm at a dead end. So far I have;

r^3 = (GMT^2) / (4(pi)^2)

r^3 = (6.67*10^(-11) * 6*10^(24)) / (4 * pi^2)

and I get

r = 21642

The book says 42.2Mm. I'm only off by a couple of million meters, hahaha.

Where am I going wrong?

Thanks,
Bernie
 
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You need to use the value of T in seconds for the constants you used to be correct.
 
Argh! Thud, thud, thud ...

That's the sound of me banging my head against the wall!

Thanks for the quick reply.

Bernie
 

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