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vktsn0303
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If v is of order δ, what is the order of ∂v/∂x and ∂2v/∂x2 ?
vktsn0303 said:If v is of order δ, what is the order of ∂v/∂x and ∂2v/∂x2 ?
What do you mean by "order"? Order is usually used in reference to derivatives, with dy/dx and ∂y/∂x being first-order derivatives, and with ##\frac{d^2y}{dx^2}## and ##\frac{\partial^2y}{\partial x^2}## being second-order derivatives.vktsn0303 said:If v is of order δ, what is the order of ∂v/∂x and ∂2v/∂x2 ?
Some context here from the OP would be helpful, although it's been a week since the question was posted, so we might never know.Battlemage! said:What if v is a derivative? So if δ were n, v would be an nth order derivative, making the other two...
Sorry, only thing that makes any sense to me. Seems to be some sort of trick question.
The order δ: ∂v/∂x & ∂2v/∂x2 refers to the order of a differential equation, which is determined by the highest derivative present in the equation. In this case, δ represents a variable order, meaning that it can take on different values depending on the specific equation being analyzed.
The order δ: ∂v/∂x & ∂2v/∂x2 is calculated by looking at the highest derivative present in the equation. For example, if the equation is ∂3v/∂x3 + 2∂v/∂x = 0, the order would be δ = 3.
The order δ: ∂v/∂x & ∂2v/∂x2 helps determine the complexity and behavior of a differential equation. It can also provide information about the number of initial conditions needed to solve the equation and the existence of a unique solution.
∂v/∂x is the first derivative of v with respect to x, while ∂2v/∂x2 is the second derivative of v with respect to x. In other words, ∂2v/∂x2 is the rate of change of the rate of change of v with respect to x.
The order δ: ∂v/∂x & ∂2v/∂x2 can affect the complexity and type of solution for a differential equation. Higher orders can lead to more complex solutions, while lower orders may have simpler solutions. Additionally, different orders may require different initial conditions for a unique solution to exist.