Is there an order-embedding from \mathbb Z^\infty to \mathbb Q for my paper?

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An explicit order-embedding from \mathbb Z^\infty to \mathbb Q is proposed using a function f that maps integers to rational numbers in the interval (0,1). The function assigns specific values to integers, allowing for the ordering of individual "letters" and creating spaces between them. The embedding g is defined as a sum that incorporates the function f and the calculated spaces, ensuring the result remains rational. The approach is confirmed to be effective for the intended purpose of the paper. This method successfully demonstrates the desired order-preserving function.
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For a paper I'm writing: Does anyone know of an explicit order-embedding (i.e. an order-preserving function) from \mathbb Z^\infty, the direct sum of infinitely many copies of the integers ordered lexicographically, to \mathbb Q, the rationals? It need not be a surjective embedding, but that would be a plus (obviously the two sets are order isomorphic).
 
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What about this?

First, define a function f: \mathbb Z \to (0,1) \cap \mathbb Q, something like
0 -> 1/2
n -> 1 - 1/(2n) for i>0
n -> -1/(2n) for i<0

This allows to order individual "letters" (I like the analogy, I will keep it).
Use this function to evaluate the position of all 1-letter-words. In addition, the space to the next word can be used for all words beginning with this letter, in a similar way (0,1) was used for 1-letter-words. Let d(n)=f(n+1)-f(n) be this space.

Now, let g: \mathbb Z^\infty \to \mathbb Q with
g(a_0,a_1,...) = \sum_i \left(f(a_i) \prod_{n=0}^{i-1} d(a_n)\right)

I hope this works...
As the sum adds up a finite number of non-zero values, the result is rational.
 
This is a great idea, exactly what I wanted. Thank you!
 
I was reading documentation about the soundness and completeness of logic formal systems. Consider the following $$\vdash_S \phi$$ where ##S## is the proof-system making part the formal system and ##\phi## is a wff (well formed formula) of the formal language. Note the blank on left of the turnstile symbol ##\vdash_S##, as far as I can tell it actually represents the empty set. So what does it mean ? I guess it actually means ##\phi## is a theorem of the formal system, i.e. there is a...

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