Ordinary differential equation question

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SUMMARY

The general solution to the ordinary differential equation (ODE) given by F = X''m, where F and m are constants, is derived through integration. The correct solution is X = (k/2)t^2 + Ct + D, where k is defined as F/m. The initial attempt mistakenly simplified the integration process, leading to an incomplete solution. The final expression incorporates both linear and quadratic terms, confirming the necessity of careful integration in solving ODEs.

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Homework Statement



What is the general solution to the following ODE

F=X''m where F and m are both constants

Homework Equations





The Attempt at a Solution



I got X=(k/2)t^2 + C

I got this from F/M being just another constant K, and X'' being (d^2 X)/(dt^2) so you just integrate k twice with respect to t, the first giving kt, and the second giving (k/2)t^2 + C. Is this correct?
 
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almost but not quite,

assuming m != 0, F = X''m => F/m = X'' , so X' = (F/m)x + C, say k = F/m, so

X' = kx + C, now integrate again,

X = kx^2/2 + Cx + D
 
yep, stupid mistake. thanks a lot!
 

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