Orthogonality/infinite series solutions differential equation

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 2K views
bossman007
Messages
60
Reaction score
0

Homework Statement



This is the problem statement in the picture for exersize 14, it's rather long (pertaining to orthogonality - which I only understand what the definition of orthogonality is, which is the "(15)" on the side of the image below.

[PLAIN]http://postimage.org/image/oxhw2uf8p/ [/PLAIN]



Homework Equations



y'' + (k^2)y = 0


The Attempt at a Solution



My attempted solution attached below has a hint for exercise 14 which I will write out at the top of the page

photo_22.jpg
 
Last edited by a moderator:
Physics news on Phys.org
When you multiply both sides of the differential equation [itex]y_n''(x)+k_n^2y_n(x)=0[/itex] by [itex]y_m(x)[/itex], you don't get [itex]y_m''(x)+k_n^2y_m(x)=0[/itex]. That's not how multiplication works.
 
Oh wow, sorry careless error!

I got this far and don't know what I'm supposed to do after this:

trigg_ex_14.jpg
 
bossman007 said:
Oh wow, sorry careless error!

I got this far and don't know what I'm supposed to do after this:

trigg_ex_14.jpg

Does [itex]k_n=k_m[/itex] for all possible values of [itex]m[/itex] and [itex]n[/itex]? If not, how do you justify cancelling out the 2 terms that you cancelled?

Rather, you should have [itex](k_m^2-k_n^2)y_m y_n = \frac{d}{dx}\left( y_my_n' - y_n y_m' \right)[/itex]. As for what to do next, just follow the hint (it is very explicit in its instructions) and integrate both sides of the equation over a full period of [itex]y_n[/itex] (you'll probably want to start by figuring out what the period of [itex]y_n[/itex] is :wink:)...what do you get?
 
Thanks so much, i got the final answer !