Orthogonality/infinite series solutions differential equation

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Homework Help Overview

The discussion revolves around a differential equation related to orthogonality in the context of infinite series solutions. The original poster shares a problem statement and expresses limited understanding of the concept of orthogonality as it pertains to the exercise.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of multiplying the differential equation by another function and question the validity of certain steps taken in the original poster's attempt. There is also a query regarding the relationship between the constants k_n and k_m, and how this affects the cancellation of terms.

Discussion Status

The conversation is ongoing, with participants providing guidance on how to proceed with the problem. Some have offered hints about integrating the equation and considering the period of the function involved, but no consensus has been reached on the final approach.

Contextual Notes

There is an indication of a hint provided in the original problem statement, which may guide the participants in their exploration. The original poster's understanding of orthogonality is noted as limited, which may affect their approach to the problem.

bossman007
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Homework Statement



This is the problem statement in the picture for exersize 14, it's rather long (pertaining to orthogonality - which I only understand what the definition of orthogonality is, which is the "(15)" on the side of the image below.

[PLAIN]http://postimage.org/image/oxhw2uf8p/ [/PLAIN]



Homework Equations



y'' + (k^2)y = 0


The Attempt at a Solution



My attempted solution attached below has a hint for exercise 14 which I will write out at the top of the page

photo_22.jpg
 
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When you multiply both sides of the differential equation [itex]y_n''(x)+k_n^2y_n(x)=0[/itex] by [itex]y_m(x)[/itex], you don't get [itex]y_m''(x)+k_n^2y_m(x)=0[/itex]. That's not how multiplication works.
 
Oh wow, sorry careless error!

I got this far and don't know what I'm supposed to do after this:

trigg_ex_14.jpg
 
bossman007 said:
Oh wow, sorry careless error!

I got this far and don't know what I'm supposed to do after this:

trigg_ex_14.jpg

Does [itex]k_n=k_m[/itex] for all possible values of [itex]m[/itex] and [itex]n[/itex]? If not, how do you justify cancelling out the 2 terms that you cancelled?

Rather, you should have [itex](k_m^2-k_n^2)y_m y_n = \frac{d}{dx}\left( y_my_n' - y_n y_m' \right)[/itex]. As for what to do next, just follow the hint (it is very explicit in its instructions) and integrate both sides of the equation over a full period of [itex]y_n[/itex] (you'll probably want to start by figuring out what the period of [itex]y_n[/itex] is :wink:)...what do you get?
 
Thanks so much, i got the final answer !
 

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