Oscillations - mass suspended from string

Click For Summary

Homework Help Overview

The discussion revolves around a problem related to oscillations involving a mass suspended from a string, focusing on the dynamics of the system and the equations governing its motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's attempts to derive an equation for acceleration and question the validity of a constant acceleration in oscillatory motion. There are suggestions to consider the forces acting on the mass and to explore the implications of different variables in the equations. Some participants propose eliminating options based on reasoning about the formulas for angular frequency.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on approaching the problem through differential equations and the dynamics of oscillatory motion. There is no explicit consensus on the correct approach or solution yet.

Contextual Notes

There are mentions of constants and variables in the equations, as well as potential confusion regarding the notation used for acceleration and displacement. Participants are encouraged to clarify these aspects as they explore the problem further.

desmond iking
Messages
284
Reaction score
2

Homework Statement


the answer is a for this question. but i don't understand how to get the solution.


Homework Equations





The Attempt at a Solution


mg-k(l-a+b)=ma

since mg=k(l-a)

-kb=ma

a=-(k/m)b

k/m=a/b

so my ans is sqrt root( a/b)
 

Attachments

  • IMG_20140621_074427[1].jpg
    IMG_20140621_074427[1].jpg
    25.4 KB · Views: 465
Physics news on Phys.org
Hi, desmond. Welcome to the forum.

a, b, and l are constants, so the equation you came up with shows a fixed, constant acceleration. As you realize, this isn't correct; a fixed acceleration is not a characteristic of oscillatory motion. Somewhere in that equation you'd need a variable x which is the extension at any moment.

It might be easier if you were to start with the options, and maybe eliminate them one by one? Look for a reason why any particular option could not be the formula for ω2.
 
Last edited:
NascentOxygen said:
Hi, desmond. Welcome to the forum.

a, b, and l are constants, so the equation you came up with shows a fixed, constant acceleration. As you realize, this isn't correct; a fixed acceleration is not a characteristic of oscillatory motion. Somewhere in that equation you'd need a variable x which is the extension at any moment.

It might be easier if you were to start with the options, and maybe eliminate them one by one? Look for a reason why any particular option could not be the formula for ω2.

so if the option of (a/b) is given, can i choose it?
 
Try getting to the differential equation given in the problem by considering what forces are acting on the mass for an arbitrary displacement.
 
Orodruin said:
Try getting to the differential equation given in the problem by considering what forces are acting on the mass for an arbitrary displacement.

can you explain further?
 
desmond iking said:
can you explain further?
Do you understand the mathematics behind x with a pair of dots above it, as it appears in the textbook question in your attachment? (Sometimes it is written x’’ )
 
Last edited:
desmond iking said:
so if the option of (a/b) is given, can i choose it?
Choose it if you wish. It's wrong though.

Oh, I just noticed: aren't you using the letter "a" for two different things in your equations in this thread??
 
Last edited:
Hint: determine the spring constant k, then use the formula for radian frequency w of a mass bobbing up & down:
w = w(k,m).

If you don't know the formula you'll have to proceed per post #4.
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
1
Views
1K
Replies
13
Views
2K
Replies
13
Views
2K
Replies
2
Views
942
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
31
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
3K
Replies
19
Views
2K