Osmolarity Calculations for 5% Glucose, .89% NaCl, and 8% Glucose Solutions

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SUMMARY

This discussion focuses on calculating the osmolarity of 5% glucose, 0.89% NaCl, and 8% glucose solutions. Participants emphasize the importance of converting percentages to molarities using density tables, which provide the necessary density values for accurate calculations. The conversion process involves determining the mass of 1 liter of the solution based on its density, which is essential for calculating osmolarity. The conversation highlights the need for practical resources, such as online density tables, to facilitate these calculations.

PREREQUISITES
  • Understanding of osmolarity and its significance in chemistry
  • Knowledge of molarity and how to convert between percentage concentrations and molarity
  • Familiarity with density tables and their application in solution calculations
  • Basic skills in using online resources for chemistry data
NEXT STEPS
  • Research how to convert weight/volume percentages to molarity for various solutes
  • Explore the use of density tables for calculating solution concentrations
  • Learn about osmolarity calculations for different types of solutions
  • Investigate online tools and resources for chemistry calculations, such as Chembuddy
USEFUL FOR

Chemistry students, educators, and professionals involved in solution preparation and analysis, particularly those needing to perform osmolarity calculations for laboratory or academic purposes.

Nouranoura
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You have to show your attempts, this is a forum policy. Also, all homework like questions should go to homework forum.
I don't know how to get the oolarity from just the percentage
See this question:
Calculate the osmolarity of each solutions:
5% glucose solution
.89% NaCl solution
And 8% glucose solution
i=1.9
 
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Convert percentages to molarities.
 
Borek said:
Convert percentages to molarities.
Yeah I know but how do I do that? Is it by using w/v %? How does the NaCl 0.89% become 8.9 g/l? That's the part that I don't get
 
Approximately: 1 L is 1 kg.

Precisely: take a density table, read the density for a given concentration, calculate mass of 1 L of the solution, follow from there.
 
Borek said:
Approximately: 1 L is 1 kg.

Precisely: take a density table, read the density for a given concentration, calculate mass of 1 L of the solution, follow from there.
I do not follow sir how is the density related to the percentage? Please forgive me I may have not understood you. English is not my first language

Borek said:
Approximately: 1 L is 1 kg.

Precisely: take a density table, read the density for a given concentration, calculate mass of 1 L of the solution, follow from there.[/QUO
 
Nouranoura said:
how is the density related to the percentage?

This is something that has to be measured. For many compounds there are ready density tables, some of them printed in chemistry handbooks, some of them available on the internet. You need to locate such a table and read the density for a given concentration.
 
Borek said:
This is something that has to be measured. For many compounds there are ready density tables, some of them printed in chemistry handbooks, some of them available on the internet. You need to locate such a table and read the density for a given concentration.
Excuse me sir I did not ask what density is, I do know what it is but my question was that why would we need the density.You see the main question is part of a sample exam paper there won't be any density tables whatsoever
 

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