What is the input voltage for the second stage in a 2-stage amplifier?

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SUMMARY

The input voltage for the second stage in a 2-stage amplifier is determined by the voltage divider effect between the output of the first stage and the input resistance of the second stage. The gain of the overall amplifier can be calculated using the formula A = A1 x A2 x (rin2 / (rin2 + ro1)), where A1 is the gain of the first stage, A2 is the gain of the second stage, rin2 is the input resistance of the second stage, and ro1 is the output resistance of the first stage. The factor 'p' represents the loading effect of the stages, confirming that the second stage input voltage is not simply Vin2 = Vin x A1, but rather Vin2 = Vin x A1 x (rin2 / (ro1 + rin2)).

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perplexabot
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Hello all. I am currently trying to find the gain of a 2 stage amp. According to some notes I have, it is:

A = A1 x A2 x (rin2 / (rin2 + ro1))
Where
A1 = gain of first stage
A2 = gain of second stage
rin2 = input resistance of second stage
ro1 = output resistance of first stage

Let p = (rin2 / (rin2 + ro1)) so that A = A1 x A2 x p

I understand conceptually why 'p' comes in. It is due to loading of the stages together (right?).
But I don't understand how to get that factor ('p') mathematically. Please explain. Thank you.

PS: If a schematic of the amplifier is needed please let me know.
 
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In electronic circuits, we always hooking the output of something (output of a amplifier, output of a voltage input source...) to the input of something else (load resistor, input stage of a next amplifier...).
After we draw this in a simplified schematics we see our old friend the voltage divider.

95_1246404388_thumb.png


p = Voltage divider equation

So the second stage input voltage is not equal to

Vin2 = Vin x A1 because we have a voltage divider in the circuit, so the second stage input voltage is equal to.

Vin2 = Vin x A1 x Rin/(Rout + Rin)
 
Last edited:

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