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Overshoot of 15% what is damping ratio

  1. Sep 28, 2014 #1
    1. The problem statement, all variables and given/known data
    A shock absorber is to be designed to limit its overshoot to ##15## percent of its initial displacement when released. Find the damping ratio ##\zeta_0## required.


    2. Relevant equations


    3. The attempt at a solution

    My question is since log decrement, ##\delta = \ln\frac{x_1}{x_2} = \frac{2\pi\zeta}{\sqrt{1 - \zeta^2}}##, for a 15% overshoot, do I set ##\frac{x_1}{x_2} = 1.15## and then solve for ##\zeta##?
     
  2. jcsd
  3. Sep 28, 2014 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    How is overshoot defined? In the way you use it it looks odd (1000% overshoot would mean a strong damping then).
    Also make sure you use the correct amplitudes to compare - after 1/2 of the oscillation or a full oscillation?
     
  4. Sep 28, 2014 #3

    donpacino

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    Gold Member

    yes
     
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