Oxidized and Reduced reaction species

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In the reaction 2Na + 2H2O → 2NaOH + H2, sodium (Na) is in the elemental state, giving it an oxidation state of 0. Hydrogen (H2) on the products side is also in its elemental form, thus maintaining an oxidation state of 0. Consequently, sodium undergoes oxidation as it loses electrons, while hydrogen is reduced as it gains electrons. The oxidation state of elements in their elemental form is always 0, confirming the oxidation and reduction processes in this reaction. This understanding is essential for analyzing redox reactions effectively.
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I was given 2Na + 2H2O → 2NaOH + H2

My only question here is whether the Na on the reactants side is 0 because it is alone? And is it the same thing for the H2 that is alone on the products side?

So if were the case Na would oxidize and H would reduce?
 
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The oxidation state of atoms in their elemental state is 0.
 
Yes, yes & yes.
 
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