1. The problem statement, all variables and given/known data Use completing the square method to rewrite the equation of the parabola y^2 – 4y – 44 = 16x in the form (y-y0)^2 = 4A(x-x0) Hence find: a) the coordinates of the vertex b) the coordinates of the focus c) the equation of the line that passes through the focus and parallel to the y-axis. y^2 - 4y - 44 = 16x at this point I thought that the only way that I could get an equation whereby I could complete the square (and in the form required) was to add 48 to both sides of the equation. which would give me y^2 - 4y + 4 = 16x + 48 and I could complete the square and in the form required. (y - 2)^2 = 16(x+3) *Vertex therefore would be (2, -3) *Focal length A = 4 *Focus S is 4 units to the right of the Vertex S(6, -3) *Equation of the line that passes through the focus and parallel to the y-axis x = -3 2. Relevant equations As above 3. The attempt at a solution As above - can someone confirm that I am on the right track with this?