Parabolic Path of a Projectile

[DJ24]

How do we know, or how can we prove that the path of a projectile is (at least part of) a parabola?

 

[nicksauce]

Easily:

In the vertical direction
<br /> F = ma = m\frac{d^2 y}{dt^2} = -mg<br />

Integrated twice we obtain
<br /> y(t) = y(0) + v_y(0)t - \frac{1}{2}gt^2<br />

Which is indeed the equation of a parabola with respect to time.

Now in the x-direction, we have
<br /> x(t) = x(0) + v_x(0)t<br />
since there is no force in this direction. It should be clear that if we re-write y(t) in terms of x(t), by solving for t in the above equation, y(t) will also be a parabola in terms of x.

 

[rcgldr]

How do we know, or how can we prove that the path of a projectile is (at least part of) a parabola?

A parabola occurs under the simplified case of a flat Earth and a constant gravitational field and no aerodynamic drag. For a spherical earth, with no drag, and the equivalent of a point source for gravity, the path is part of an ellipse.