Paradox of Obtuse Angles in the Sine Rule

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Homework Help Overview

The discussion revolves around the sine rule in the context of obtuse angled triangles. Participants explore the relationship between angles and the lengths of the sides opposite those angles, particularly questioning how the sine of an obtuse angle can be less than that of an acute angle while still adhering to the geometric properties of triangles.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the sine rule when applied to obtuse angles, questioning whether the side opposite the obtuse angle can indeed be the longest. They also consider scenarios where the circumradius is fixed and how that affects the lengths of the sides.

Discussion Status

The conversation is ongoing, with some participants suggesting that the apparent contradiction may resolve itself under certain conditions, such as keeping the circumradius constant. Others are exploring specific examples and ratios of sides based on given angles, indicating a productive exploration of the topic.

Contextual Notes

Participants are examining specific angle configurations in triangles, such as 30, 45, and 105 degrees, and discussing the resulting side ratios derived from the sine rule. There is a recognition of potential misconceptions regarding these ratios.

ritwik06
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I have read the sine rule:
It states-->
sin A/a=sin B/b=sin C/c = 1/2R

where R is circumradius.
Now,
a=2Rsin A
b=2Rsin B
c=2Rsin C

For a triangle R is fixed.
In an obtuse angled triangle, the side opposite largest angle is the longest(geomtrically)

But the sine of an obtuse angle can be less than that of an acute angle. How is this possible? Is it possible that the side opposite obtuse angle isn't the largest? Or is the sin rul giving a wrong stand in this case??
 
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ritwik06 said:
For a triangle R is fixed.
In an obtuse angled triangle, the side opposite largest angle is the longest(geomtrically)

But the sine of an obtuse angle can be less than that of an acute angle. How is this possible? Is it possible that the side opposite obtuse angle isn't the largest? Or is the sin rul giving a wrong stand in this case??

Hi ritwik06! :smile:

Yes, I see what you mean …

if A is obtuse, then as A increases, sinA decreases, but a (the side a) actually increases though it should decrease!

hmm :rolleyes:

ah, but that's assuming that b and c are constant, in which case R is not constant, so everything sorts itself out.

But if you keep R constant, so that, say, the "C" end of side a slides round the circle, then as A increases, the "C" end will get closer, and therefore a will actually decrease, (and so will b) …

there isn't actually a problem. :smile:
 
tiny-tim said:
Hi ritwik06! :smile:

Yes, I see what you mean …

if A is obtuse, then as A increases, sinA decreases, but a (the side a) actually increases though it should decrease!

hmm :rolleyes:

ah, but that's assuming that b and c are constant, in which case R is not constant, so everything sorts itself out.

But if you keep R constant, so that, say, the "C" end of side a slides round the circle, then as A increases, the "C" end will get closer, and therefore a will actually decrease, (and so will b) …

there isn't actually a problem. :smile:

Suppose the angles of a triangle are 30,45, 105!
what will be the ratio of their sides?
2:[tex]\sqrt{2}[/tex]:[tex]\sqrt{3}+1[/tex]?

as I get by sin rule. Isnt it?

does that mean that the side opposite 30 is greater than the one opposite 45?
 
ritwik06 said:
Suppose the angles of a triangle are 30,45, 105!
what will be the ratio of their sides?
2:[tex]\sqrt{2}[/tex]:[tex]\sqrt{3}+1[/tex]?

No, the ratio of the sides is 1/2 : 1/√2 : (√3 + 1)/2√2,

or √2 : 2: √3 + 1 :smile:
 
tiny-tim said:
No, the ratio of the sides is 1/2 : 1/√2 : (√3 + 1)/2√2,

or √2 : 2: √3 + 1 :smile:

I am sorry! Thanks for pointing out my misconception. Thanks a lot!
 

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