Can You Simplify a Parallel Adder SOP Expression Using Karnaugh Maps?

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The discussion focuses on simplifying a parallel adder's Sum of Products (SOP) expression using Karnaugh Maps. The user initially presents their working expressions for outputs S3, S2, S1, and S0, along with a minterm representation for F. They realize a mistake in their formula regarding the carry input and seek clarification on the relationship between output F and inputs ABCD. The conversation emphasizes treating the system as a black box and suggests using an Excess-3 table for comparison. Ultimately, the user acknowledges the complexity they added and confirms they have resolved their confusion.
kukumaluboy
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My working:
S3 = A
S2 = B
S1 = C'
S0 = D'

F = Sum-Minterm(0, 1, 2, 4, 5, 8) (Basically i find when is X smaller then Y)
Used Kmap to arrive at
A'C' + B'C'D' + A'B'D'

Am i correct?
 
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Did you check your result? If ABCD = 1111, what should F be?
 
Ok my formula was Si = Xi XOR Yi XOR C

That was wrong. Should be Ci. hmmmm

I need clue bro lol
 
Focus on the relationship between the output F and the inputs ABCD. In other words: treat the whole thing as a black box with inputs ABCD and output F.
 
So must i like do the excess-3 table and compare ab < cd values
 
"Excess-3", strictly speaking, operates on BCD (binary coded decimal) values. Since the input is not constrained to BCD, it's better to say "So must I like just add 3 to the input..."

Not making fun, just trying to make a fine point. And yes, then do the comparison.
 
yeayea! thank you man solved it lol. I was thinking it too complicatedly.
 

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