1. The problem statement, all variables and given/known data Consider the beam shown in (Figure 1) . Suppose that a = 15 in. , b = 8 in. , c = 1 in., and d = 4 in. Determine the moment of inertia for the beam's cross-sectional area about the x axis. https://www.google.com/search?q=Det...iw=767&bih=740&dpr=1.25#imgrc=FBSvRrNrtgG_OM: 2. Relevant equations Ix=Ix'+ACy^2 Where Cy is the centroid, so ΣACy=Σ(A*Cy) then ΣACy/ΣA=Cy 3. The attempt at a solution I got Cy to be 1.86 inches I then started to use the Ix expression: (1/12)(x)(y)^3+(x)(y)(Cy)^2 I made sure to break it into squares and subtract values that overlap ex: squares thats are 1x4, 1x13, and 1x8 I've done it two different ways and keep getting 109.8 in^4 as Ix and the homework system says that's not right.