Parallel Forces: Painter on scaffold x meters from 1 end.

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SUMMARY

The discussion centers on the concept of choosing a center of rotation in physics, specifically in the context of a painter on a scaffold. The example provided involves a painter weighing 150 lbs on a 6 ft scaffold positioned 2 ft from one end, leading to the calculation of forces at both ends of the scaffold. The calculations reveal that if F1 is the force at one end and F2 at the other, F1 equals 100 lbs and F2 equals 50 lbs when using the end of the scaffold as the pivot point. The discussion raises questions about the implications of selecting different points of rotation and whether there are infinite or finite choices for these points.

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Ocata
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Hi,

My book says that although there is a natural point of rotation, we can however choose any point as a center of rotation. But without explaining further, it goes directly to an example where the endpoint is the center of rotation.

I would like to know what the book means by being able to choose any point as a center of rotation.

For example,
A painter weighing 150lbs is standing on a 6ft scaffold at a distance of 2 ft from one end. How much weight must each end of the scaffold hold?

F1 + F2 = 150lbs

Torque = Torque
Fs = Fs
150lbs(2ft) = F2(6ft)
F2 = 50lbs

So F1 + F2 = 150lbs
F1 + 50lbs = 150lbs
F1 = 100lbs

Here, F1 was the point of rotation. But how can this problem be approached if a different point of rotation is considered? And is there an infinite number of choices for points of rotation? Or is there a finite number of possible points/centers of rotation?
 
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Let's say you chose a point of rotation on the scaffold, 0<x<6.
Then if F1 is placed at 0 and F2 placed at 6, you still have to balance the forces.
 
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Thank you RUber.
 

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