# Definition of Moment & Explanation of Vectors, Forces, & Angular Momentum

• Greg Bernhardt
In summary, a moment is a cross-product of a position vector with a vector such as a force or momentum. It is a pseudovector and follows the rules of vector addition. In most exam questions, all moments are parallel to each other and can be treated as numbers instead of vectors. The moment of force is also known as torque, and the moment of momentum is also called angular momentum. The parallel axis theorem states that the total moment of inertia is equal to the moment of inertia at the center of mass plus the product of mass and the square of the distance from the center of mass to the axis. Moments can be taken about any point, and it is usually chosen to make calculations easier. Moments about an axis are independent of the
Definition/Summary

The moment of a vector is the cross-product of the position vector with that vector (e.g., a force or momentum vector).

So it is is a vector (strictly, a pseudovector), and obeys the rules of vector addition.

Moment of momentum is more usually called angular momentum.

In most examination questions, all the vectors are in the same plane (the plane of the examination paper), and so all the moments are parallel to each other (and perpendicular to the paper), and so they can all be treated as numbers instead of vectors.

Equations

Moment of force = Torque: $\mathbf{\tau}= \mathbf{r} \times \mathbf{F}$

Moment of momentum = Angular Momentum: $\mathbf{\mathcal{L}}=\mathbf{r}\times \mathbf{p}$

Cross-product of Newton's second law with a fixed position vector $\mathbf{r}$ gives:

$$\mathbf{r} \times \sum \mathbf{F} = \mathbf{r} \times \frac{d \mathbf{p}}{dt}$$

But $d/dt(\mathbf{r} \times \mathbf{p}) = \mathbf{r} \times (d\mathbf{p}/dt)$ since $(d \mathbf{r}/dt )\times \mathbf{p} =0$, giving:

$$\mathbf{\tau}_{total}\equiv\sum\mathbf{r} \times \mathbf{F}=\frac{d}{dt}(\mathbf{r} \times \mathbf{p})= \frac{d \mathbf{\mathcal{L}}}{dt}$$

i.e., total moment of force = rate of change of total angular momentum

A rigid body at each instant of time rotates about an axis.

Its total Moment of momentum (Angular Momentum) about any point on that axis is its Moment of Inertia about that axis times its angular velocity:

$$\mathbf{\mathcal{L}} = I \mathbf{\omega}$$

By the Parallel Axis Theorem, this is equal to:

$$\mathbf{\mathcal{L}} = (I_C\,+\,Md^2) \mathbf{\omega}$$

where M is the total mass, d is the distance from the centre of mass to that axis, and $I_C$ is the Moment of Inertia about the parallel axis through the centre of mass.

Extended explanation

Every force F has a moment about any point P.

To find the moment, draw R, the point of application of the force, and L, the line of the force, and draw the perpendicular line PQ from P to L (so both Q and R lie on L).

For the Moment of a velocity, R is the position of the centre of mass, and L is the line of the velocity.

Then the moment of F about P is the vector written "r x F" (pronounced "r cross F"), where r is the position vector PR. Its direction is perpendicular to both L and the line PR (and PQ). And its magnitude is PQ times F.

PQ is sometimes called the lever arm.

Note that if P is on the line L, then P = Q, so PQ = 0, so the moment of the force is 0.

In nearly all exam problems, everything is in the same plane (the plane of the examination paper!), so all the moment vectors are vertically out of the page.

In other words, they're all parallel to each other, so we can forget that they're vectors, and treat them simply as numbers, PQ times F.

We can take moments about any point, so we always choose whatever point makes the calculations easiest.

Usually, it's the point of application of an unknown force, so that the moment of that force is 0, making the equation shorter!

Moment about a point is a vector, and so it has a component in any direction:

$$(\mathbf{r}\times\mathbf{F})\cdot\hat{\mathbf{k}}\$$​

Moment about an axis is simply the component in the direction of that axis of the moment about any point on that axis.

It is independent of which point on the axis is chosen:

$$((\mathbf{r}\,+\,a\hat{\mathbf{k}})\times\mathbf{F})\cdot\hat{\mathbf{k}}\ =\ (\mathbf{r}\times\mathbf{F})\cdot\hat{\mathbf{k}}\ +\ a(\hat{\mathbf{k}}\times\mathbf{F})\cdot \hat{\mathbf{k}}\ =\ (\mathbf{r}\times\mathbf{F})\cdot\hat{\mathbf{k}}$$

* This entry is from our old Library feature. If you know who wrote it, please let us know so we can attribute a writer. Thanks!

Thanks for the overview of moments in physics

## What is a moment?

A moment is a measure of the tendency of a force to rotate an object about a specific point or axis. It is calculated by multiplying the magnitude of the force by the perpendicular distance from the point or axis to the line of action of the force.

## What are vectors?

Vectors are quantities that have both magnitude and direction. They are represented by arrows, with the length of the arrow representing the magnitude and the direction of the arrow representing the direction. Vectors are used to represent physical quantities such as displacement, velocity, and force.

## What are forces?

Forces are interactions between two objects that cause a change in motion. They can be described as pushes or pulls and are represented by vectors. Forces can be caused by contact between objects or by non-contact interactions such as gravity or magnetism.

## What is angular momentum?

Angular momentum is a measure of an object's tendency to resist changes in its rotational motion. It is calculated by multiplying the moment of inertia (a measure of an object's resistance to rotational motion) by its angular velocity (rate of rotation).

## How are vectors, forces, and angular momentum related?

Vectors are used to represent forces and angular momentum. Forces and angular momentum are both physical quantities that have both magnitude and direction, making them vector quantities. Additionally, forces can cause changes in an object's angular momentum, as forces can cause rotation. Angular momentum can also influence the direction and magnitude of forces acting on an object.

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