Eight lights are connected in parallel to a 110-V source by two long leads of total resistance 1.97 Ω.
a) If 405 mA flows through each bulb, what is the resistance of each?
Rtotal(for a series)= (R1-1+R2-1)-1
Rtotal(for parallel)= R1+R2
The Attempt at a Solution
So I tried just setting what I assumed was the total resistance (1.97) equal to my derived equation (Rtot=(8R-1)-1) and came up with 15.76 Ohms. This was wrong.
So then I tried using V=IR, and got 271.605. This was also wrong.
Upon re-looking at the problem, I see that (I think) it means the total resistance 1.97 Ohms is actually just of the two long leads, in which case I'm not sure how to work this into the problem... :/