Parallel plane containing a line

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SUMMARY

The task is to find the equation of a plane that contains the line defined by the parametric equations x=3+2T, y=T, z=8-T and is parallel to the plane represented by the equation 2x + 4y + 8z = 17. The correct form for the parallel plane is 2x + 4y + 8z + D = 0. To determine the value of D, substitute a point from the line, such as (3, 0, 8), into the plane equation, which confirms that the plane contains the line.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of plane equations in three-dimensional space
  • Familiarity with the concept of parallel planes
  • Ability to substitute coordinates into equations
NEXT STEPS
  • Study the derivation of plane equations from points and normal vectors
  • Learn about the geometric interpretation of parallel planes
  • Explore methods for converting between parametric and Cartesian forms of equations
  • Investigate the implications of line-plane intersections in three-dimensional geometry
USEFUL FOR

Students studying geometry, particularly those focusing on three-dimensional space, as well as educators teaching concepts related to planes and lines in mathematics.

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Homework Statement
Find the plane that contains the line x=3+2T, Y=t, Z=8-t and is parallel to the plane 2x + 4y +8z =17.

The attempt at a solution

It seemed to me that since the plane is parallel to the plane 2x+4y+8z=17, it must be of the form 2x+4y+8z+D=0 so that it would be parallel.
(Is that true?)

Anyways, I then converted the equation of the line out of parametric into (x-3)/2 = Y = -(Z-8).
(I know that part's right.)

But now I'm not sure what to do. Ideas?
 
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Yes, your parallel plane equation is correct. Now just substitute x, y and z from the line equation into the plane equation and figure out what D must be.
 
It is, in fact, sufficient to use a single point on the line. Do you see why? For example, it should be easy to find D such that (3, 0, 8) (taking T= 0 in the equations of the line) is on the plane.
 

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