Parallel-plate capacitor charge problem

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The discussion revolves around calculating the charge on a parallel-plate capacitor formed by two 10.0 cm diameter electrodes spaced 0.56 cm apart, connected to a 14V battery. The formula used is C = K*A/d, leading to a calculated charge of 1.74 x 10^-10 coulombs after disconnecting the battery. The answer is confirmed to be 1.7 x 10^-10 coulombs when expressed in two significant digits. Participants emphasize the importance of including units in calculations and suggest verifying dimensions for accuracy. Overall, the focus is on ensuring correct application of formulas and significant figures in the capacitor charge problem.
Allyson
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Homework Statement


Two 10.0 -diameter electrodes 0.56 apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 battery. After a long time, the capacitor is disconnected from the battery but is not discharged.
a. What is the charge on each right after the battery is disconnect? What is q1, q2 in coulombs


Homework Equations


C=K*A/d


The Attempt at a Solution

I have tried several attempts, but still have the answer 1.74*10^-10. What have I done wrong.
 
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This is how I did the work.
pi*.01/4=.007853982*8.85418/.0056=12.42*10^-12*14=1.74*10^-10, 1.7*10^-10 Answer in 2 significant digit?
 
Is one saying that 1.7*10^-10 is the answer?

1.74*10^-10 in two significant digits would be 1.7*10^-10.


It would also help if one provides units. I would guess the capacitor plates have a 10 cm dia, and are 0.56 cm apart?

Also, please write all the equations. Please see - http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capac.html
 

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