A capacitor is constructed from 2 square metal plates. A dielectric k= 4.93 fills the upper half of the capacitor and a dielectric k=10 fills the lower half of the capacitor. Neglect edge effects. The plate are separated by a distance of 0.37 mm and the length of the plates is 27 cm. Calculate the capacitance C of the device. Answer in units of pF.(adsbygoogle = window.adsbygoogle || []).push({});

I used the equation for C of a parallel plate capacitor.

[tex] kE_o A/d + kE_o A/d [/tex]

Where the area= 3.7 x 10^-4 * .135 = 4.995 x 10^-5

So (4.93)(8.85 x 10^-12)(4.995 x 10^-5)/ 3.7 x 10^-4 + (10)(8.85 x 10^-12)(4.995 x 10^-5)/ (3.7 x 10^-4)

= 1.78 x 10^-11 F.

Converting to pF gave me 1.78 x 10^-23 which isn't right... help please?

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# Parallel plate capacitor problem

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