Parallel plate - uniform electric field help

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SUMMARY

The discussion centers on calculating the final speed of an electron in a parallel-plate uniform electric field with a strength of 325 N/C. The electron, with a charge of 1.6 × 10-19 C and a mass of 9.11 × 10-31 kg, is released from rest and moves 3.2 cm. To find the final speed, the kinetic energy (KE) equation, Ek = 0.5mv2, is utilized, and the relationship between electric field strength and work done on the charge must be applied to determine the final kinetic energy.

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Homework Statement


A parallel-plate uniform electric field with a strength of 325 N/C is oriented as shown below. An electron (q = 1.6 × 10-19 C, m = 9.11 × 10-31 kg) is released (from rest) inside the field and moves 3.2 cm to the left. What is the final speed of the electron at the end of the 3.2-cm distance?


Homework Equations





The Attempt at a Solution


I did this:
Ek=.5mv2
Ek= .5(09.11 × 10-31)(0)2 and got 0... :/ any help would be appreciated.. I don't know where to start
 
Last edited:
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well you've done right so far. you have got the initial KE of the electron, which is zero. For now, try to find the final KE (and then afterwards, you can get final speed). So, in this situation, how can you find the final KE? What physics principles can you apply?
 

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