Parallel plates - direction of electric field

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SUMMARY

The direction of the electric field between the plates of a parallel plate capacitor is determined by the induced current resulting from a decreasing magnetic field, as explained by Lenz's Law. When the magnetic field decreases, it induces a counteracting current that flows counterclockwise (CCW), leading to a positive charge accumulation on the lower plate and a negative charge on the upper plate. Consequently, the electric field (E field) points upward, from the bottom plate to the top plate. The strength of the E field can be analyzed using Gauss's Law with the formula σ/(2ε₀).

PREREQUISITES
  • Understanding of Lenz's Law and its application in electromagnetic induction
  • Familiarity with the concept of electric fields in capacitors
  • Knowledge of Gauss's Law for calculating electric fields
  • Basic principles of magnetic fields and their changes over time
NEXT STEPS
  • Study Lenz's Law in detail to understand induced currents
  • Learn how to apply Gauss's Law for different charge distributions
  • Explore the relationship between electric fields and magnetic fields in electromagnetic theory
  • Investigate the behavior of capacitors in varying magnetic environments
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding electromagnetic induction and capacitor behavior in changing magnetic fields.

michaelw
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Indicate the direction of the electric field between the plates of the parallel plate capacitor shown in the drawing if the magnetic field is decreasing in time. Give your reasoning.

Please help me.. how can i do this?
 

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Try understanding the physics of the situation before asking the question so abruptly---

You would do well to recall Lenz Law... and with it, tell yourself what the direction the induced current in the wire will be (CW or CCW) ? Then decide how that would effect the E field between the capacitor plates.

Oh and might I add... your right hand would most certainly be helpful!
 
Last edited:
not left hand :/?
 
Use left hand when dealing with electrons fired thru H fields :D
 
would the E field be up? (the magnetic field would be decreasing over time, so the induced magnetic field would have to oppsoe the change, and therefore point out of page. the current goes up when magnetic field points out, so the current will create a + charge on lower end of capacitor, - on upper, so E field points up)
 
current will go CCW right?? (god i hate conventional current)
 
Hehe, yep you're absolutely right... imagine some unknown entity wishing to fire extra H field upward, since the H field is decreasing... so in using your right hand, you want to point your thumb in the direction of that entity is wishing to fire the H field, and your fingers will naturally curl around in the direction the induced current is traveling... in this case it is CCW like you stated!

So yes, positive charge will accumulate on the bottom plate, and negative on the top... thus creating an E field going from the bottom plate to the top plate--- as for finding the strength of the E field... I doubt you'd be required to ever do that, however you'd analyze using Gauss and apply sigma/2epsilonnaught or whatnot.
 

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