Parallel RL Circuit: Get Help with AC Supply & Differential Equation

[ng]

SGT,Thankyou very much indeed.
I think i got the stuff in my head atlast.
Thankyou.

 

[ng]

but then sgt,i also read that ip shud be assumed as
acos(wt+phi) + bsin(wt+phi)
not Kcos(wt+phi) as the supply is Vcos(wt+phi).they need not be in phase...
i am confused now.

 

[SGT]

but then sgt,i also read that ip shud be assumed as
acos(wt+phi) + bsin(wt+phi)
not Kcos(wt+phi) as the supply is Vcos(wt+phi).they need not be in phase...
i am confused now.

No, you make
i_P = K cos(\omega t + \phi_1)
where \phi_1 \neq \phi
if you make
i_P = A cos \omega t + B sin \omega t
the phase angle \phi_1 will be automatically calculated:
A = K cos \phi_1 and B = K sin \phi_1

 

[ng]

okay sgt,now i get it.
thanx a loooooooooooooot!