RL Circuit Refresher: Solve Total Current

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Discussion Overview

The discussion revolves around calculating the total current in a parallel RL circuit, focusing on the application of formulas and the correctness of calculations. Participants are exploring the implications of using different approaches and formulas in their calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a calculation for total current using given values for voltage, resistance, and inductive reactance, but questions the accuracy of their result.
  • Another participant suggests that admittances in parallel should be added, implying a different approach to the problem.
  • A participant corrects their earlier statement about the formula, indicating a mistake in the placement of a variable.
  • Further comments highlight a perceived algebraic error in the original post, suggesting that the calculations may not be correct.
  • Participants express a sense of camaraderie regarding common mistakes in calculations and acknowledge each other's contributions to clarifying the issue.

Areas of Agreement / Disagreement

There is no clear consensus on the correct approach to calculating the total current, as participants present different methods and corrections without resolving the discrepancies in their calculations.

Contextual Notes

Participants note potential errors in algebra and formula application, but the specific assumptions or definitions that might affect the calculations are not fully explored.

Who May Find This Useful

This discussion may be useful for individuals studying electrical engineering concepts, particularly those focusing on RL circuits and current calculations.

jendrix
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Hi, I have just been refreshing my theory and was going over a parallel RL circuit, like this one.

vFu2isf.png


The site I was reading had this for the total current

wSOg5fX.png


I tried some values as a test but it doesn't give me the correct answer, for total current. eg if I set
V=10V
R=2.5ohm
jXl=5ohm

Then IR=10/2.5 =4A

IL=10/5=2A

IT=√42 +22 =4.47A

However when I try the formula from the second answer I get 10/(2.5-2j) which following the maths gives me 2.44+1.95j=3.12A

Am I going wrong somewhere or is it the formula?Thanks
 

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jendrix said:
However when I try the formula from the second answer I get 10/(2.5-2j) which following the maths gives me 2.44+1.95j=3.12A

Admittances in parallel add. That should be your approach.

upload_2018-8-8_21-15-30.png

A 'Site', you said ? If it's on the internet it must be right, eh ? See my signature.....

see if that works any better.

old jim
 

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Oops ----- make that it equals Vin X ( 1/R -j1/ωL )

i put my j in wrong place . :cry:
 
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jim hardy said:
Oops ----- make that it equals Vin X ( 1/R -j1/ωL )

i put my j in wrong place . :cry:

Seems we can't even trust Old Jim when he posts at the internet with a computer, cause we can never trust a computer with anything important :-p

Ok seriously speaking that was a minor mistake, I didn't notice it either, I just noticed the huge mistake in the algebra in the OP.
 
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i do that all the time. I'm just clumsy.

Thanks @Delta2
 
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jim hardy said:
i do that all the time. I'm just clumsy.

Thanks @Delta2

Thanks Jim for clearing that up
 
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