Parametric Equation of Perpendicular Line Through Point of Intersection L1/L2

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To find the parametric equations of a line perpendicular to lines L1 and L2, the first step is to determine the point of intersection of these lines by solving a system of equations. The slopes of the lines must be analyzed, as the line perpendicular to them will have a direction vector that is the negative reciprocal of the slopes. In three-dimensional space, the cross product of the direction vectors of L1 and L2 can be used to find a vector that is perpendicular to both. The discussion emphasizes the importance of understanding the geometric relationships between the lines and the correct application of vector operations. The solution requires careful consideration of both the intersection point and the direction vector for the perpendicular line.
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1. The problem statement, all variables and given/known

Determine parametric equations of the line that Is perpendicular to the lines L1= 3t-2
2t
3t

L2= s-1
2s-7
3s-12

And passes through the point of intersection of lines L1 and L2

2. Homework Equations Parametric equation format:
x= x_1 +at
y= y_1 +bt
z= z_1 +ct

3. The Attempt at a Solution

We'll I'm given 2 sets of lines, I know that for something to be perpendicular I have to have the negative reciprocal of the slope.

But should my first step be to find the point of intersection of L1 and L2? Would I do this by solving a system of equations?
 
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yazz912 said:
1. The problem statement, all variables and given/known

Determine parametric equations of the line that Is perpendicular to the lines L1= 3t-2
2t
3t

L2= s-1
2s-7
3s-12

And passes through the point of intersection of lines L1 and L2



2. Homework Equations


Parametric equation format:
x= x_1 +at
y= y_1 +bt
z= z_1 +ct


3. The Attempt at a Solution

We'll I'm given 2 sets of lines, I know that for something to be perpendicular I have to have the negative reciprocal of the slope.
Keep in mind that the lines are in three dimensions. If you have two vectors in space, a third vector that is perpendicular to the first two vectors can be obtained from the cross product.
yazz912 said:
But should my first step be to find the point of intersection of L1 and L2? Would I do this by solving a system of equations?

yazz912 said:
 
Im sorry do you Mind elaborating a little bit more for me?
So does that mean I can choose any two vectors from those three lines and just cross? Do this for both L1 and L2?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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