Undergrad Why Must ##\mu_1, \mu_2## = ##\mu_1^*, \mu_2^*##? Parametric Resonance

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The discussion centers on proving that the values of μ1 and μ2 are equal to μ1* and μ2* given the conditions μ1μ2 = μ1*μ2* = 1 and μ1 + μ2 = μ1* + μ2*. It is suggested that by taking the complex conjugate of the equation, one can derive that μ1μ2 equals 1. The expansion of the product of two complex numbers, u1 = (a + bi) and u2 = (c + di), leads to the equations (ac - bd) = 1 and (ad + bc) = 0. These relationships provide a foundation for further exploration of the equality of the sums. The discussion highlights the challenge in proving the equality of the sums despite the established product equality.
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Why ##\mu_1, \mu_2## must be the same as ##\mu_1^*, \mu_2^*## ?

What I thought is : If ##\mu_1\mu_2 = \mu_1^*\mu_2^*## and ##\mu_1+\mu_2 = \mu_1^*+\mu_2^*##, then ##\mu_1, \mu_2## are the same as ##\mu_1^*, \mu_2^*##

It can be shown by taking the complex conjugate of (27.5) that $$\mu_1\mu_2 = \mu_1^*\mu_2^*=1$$
Now it is to be proven that ##\mu_1+\mu_2 = \mu_1^*+\mu_2^*##.
Any help would be appreciated.
 
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If u1 = (a + bi) and u2 = (c + di), then you can write (a + bi)(c + di) = 1. Expanding it, you get:

ac + adi + bci – bd = 1. Rearrange as (ac – bd) + i(ad + bc) = 1. So (ac – bd) = 1, and (ad + bc) = 0. You may be able to get a starting point from that. If possible, I will try to come back and revisit this.
 
scottdave said:
If u1 = (a + bi) and u2 = (c + di), then you can write (a + bi)(c + di) = 1. Expanding it, you get:

ac + adi + bci – bd = 1. Rearrange as (ac – bd) + i(ad + bc) = 1. So (ac – bd) = 1, and (ad + bc) = 0. You may be able to get a starting point from that. If possible, I will try to come back and revisit this.
Thanks for your help. But still could not get it.
 
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