Partial derivative second order

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Homework Help Overview

The discussion revolves around the calculation of a second-order partial derivative, specifically in the context of a problem labeled as 6.1 ii). Participants express uncertainty about their approach to the problem, particularly as they are new to the concept of partial derivatives.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • One participant attempts to compute the second-order partial derivative using the quotient rule and shares their working steps. Another participant questions the choice of the quotient rule and suggests considering the chain rule instead, indicating a preference rather than a definitive method. There is also a discussion about the clarity of the previous part of the problem (6 i) in relation to the current one (6 ii).

Discussion Status

The conversation includes attempts to clarify the methods used for differentiation and acknowledges that the original poster's calculations are correct. Participants are exploring different approaches to the problem without reaching a consensus on the best method.

Contextual Notes

Participants note that the original poster is new to the topic of partial derivatives, which may contribute to their uncertainty in approaching the problem.

Taylor_1989
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Homework Statement


Hi guys, I am have a problem with the question displayed below:

upload_2017-2-15_23-33-6.png
[/B]

Its 6.1 ii) I am really not sure how I am suppose to approach this. I am new to partials, so any advice would be great.

Homework Equations

The Attempt at a Solution


So far I have:
$$\frac{\partial ^2 f}{\partial x^2}=\frac{\partial}{\partial x}\frac{\partial f}{\partial x}=\frac{\partial}{\partial x}\frac{-x}{r^3} $$

using quotient rule:

$$=[\frac{\partial}{\partial x}(-x)(r^3)-(-x)(\frac{\partial}{\partial x}r^3)]/r^6$$

$$\frac{\partial}{\partial x}r^3=3r^2\frac{\partial r}{\partial x}=3r^2*(x/r)=3rx$$

subbing the above into the quotient and simplifying
I get
$$\frac{-r^2+3x^2}{r^5}$$

[/B]
 
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Taylor_1989 said:
using quotient rule:
might not be the best thing to do. How did you find ##\partial f\over\partial x## ?
And: was 6 i) all right and clear ? How come 6 ii) is then problematic ?

[edit] Stupid me o:) . Your working is completely correct. Well done...
'Quotient rule' confused me, but it works just fine. My approach would be to use the chain rule -- with, of course, the same result. Matter of preference, not matter of 'best thing to do'.
 
Last edited:
Taylor_1989 said:

Homework Statement


Hi guys, I am have a problem with the question displayed below:

View attachment 113277[/B]

Its 6.1 ii) I am really not sure how I am suppose to approach this. I am new to partials, so any advice would be great.

Homework Equations

The Attempt at a Solution


So far I have:
$$\frac{\partial ^2 f}{\partial x^2}=\frac{\partial}{\partial x}\frac{\partial f}{\partial x}=\frac{\partial}{\partial x}\frac{-x}{r^3} $$

using quotient rule:

$$=[\frac{\partial}{\partial x}(-x)(r^3)-(-x)(\frac{\partial}{\partial x}r^3)]/r^6$$

$$\frac{\partial}{\partial x}r^3=3r^2\frac{\partial r}{\partial x}=3r^2*(x/r)=3rx$$

subbing the above into the quotient and simplifying
I get
$$\frac{-r^2+3x^2}{r^5}$$
[/B]

Your answer is correct. It is a matter of taste whether you leave your final numerator as ##3x^2-r^2##, or re-write it as ##2x^2-y^2-z^2##.

BTW: Remove all those offensive bold fonts: it looks like you are yelling at us.
 
thank for the responses. I will remove bold next, i did not even notice it was bold.
 

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