Partial Derivatives and The Chain Rule

Click For Summary

Homework Help Overview

The discussion revolves around the rates of change of various quantities related to a box whose dimensions are changing over time. The specific quantities in question include the volume, surface area, and length of the diagonal of the box, given certain rates of change for the length, width, and height.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations for the volume and surface area, while expressing difficulty with the calculation of the diagonal's rate of change. There are questions about the correctness of initial calculations and the method for determining the diagonal length.

Discussion Status

Some participants have confirmed the correctness of their calculations for the volume and surface area, while others are exploring how to derive the rate of change for the diagonal. There is an ongoing exchange about the necessary steps to find the diagonal length and how to apply the chain rule appropriately.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a focus on ensuring that the calculations align with the given rates of change for the box's dimensions.

ktobrien
Messages
27
Reaction score
0

Homework Statement


The length l, width w, and height h of a box change with time. At a certain instant the dimensions are l = 7 m and w = h = 9 m, and l and w are increasing at a rate of 6 m/s while h is decreasing at a rate of 3 m/s. At that instant find the rates at which the following quantities are changing.
(a) The Volume
(b) The Surface Area
(c) The Length of the Diagonal

Homework Equations


L2=l2+w2+h2

The Attempt at a Solution


I have already done part a and part b but I'm having trouble with c.
I tried to work it out and got 42m/s but this is incorrect. Some help please?
 
Physics news on Phys.org
42m/s is way too high. Just by gut feeling. How did you get that?
 
2l(dl/dt)+2w(dw/dt)+2h(dh/dt)
for A I got 675m^3/s
for B I got 312m^2/s
 
If L^2=l^2+w^2+h^2 then 2L(dL/dt)=2l(dl/dt)+2w(dw/dt)+2h(dh/dt). You want to solve for the dL/dt part. Don't forget to divide by the L. I didn't check the other ones. Do I need to?
 
No the other ones are right. I have already checked them. How do I get L to know what to divide by? Do I just plug in the original l w h to find L?
 
ktobrien said:
No the other ones are right. I have already checked them. How do I get L to know what to divide by? Do I just plug in the original l w h to find L?

Absolutely.
 
Thanks a lot. I figured it was something simple like that.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
4K