Partial derivatives boundery point problems

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Homework Help Overview

The problem involves finding the largest and shortest distances from the origin to a conic defined by the equation 6x² + 4xy + 3y² - 28 = 0. The task also includes determining the lengths of the semi-axes of the conic.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to isolate terms using the Lagrange identity and considers substituting into a distance formula. Some participants suggest using polar coordinates as a potentially simpler method, while others question how this approach would be beneficial.

Discussion Status

The discussion includes various approaches to the problem, with some participants offering alternative methods and questioning the effectiveness of the original poster's strategy. There is no explicit consensus on the best approach, but guidance has been provided regarding starting with linear equations derived from differentiation.

Contextual Notes

The original poster expresses difficulty in isolating terms and mentions a lack of known values for certain variables, which may be impacting their progress.

Liquidxlax
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Homework Statement



find the largest distance and shortest distance from the origin to the conic whose equation is

6x2 + 4xy +3y2 - 28=0

and hence determine the lengths of the semi axes of this conic

Homework Equations



Lagrange identity

F= f + λφ = 0

distance = d2 =x2+ y2+ z2

The Attempt at a Solution



This has been my problems since grade 11... i have a hard time isolating a single term.

Either i want to sub in an equation into the distance formula which is only 2d for this problem or i need to use the Lagrange identity.

if Lagrange

partial x = 2x + λ(12x +4y) = 0

partial y = 2y +λ(6y+4x) = 0

any help is appreciated.
 
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Hi Liquidxlax! :wink:

Wouldn't it be easier to just use polar coordinates? :smile:
 
I'm not sure how polar coordinates will help. Just go ahead an do it. Solve the first equation for x and substitute that into the second equation. What do you get? Does that tell you something about lambda?
 
Dick said:
I'm not sure how polar coordinates will help. Just go ahead an do it. Solve the first equation for x and substitute that into the second equation. What do you get? Does that tell you something about lambda?

what about the d^2? It has no known value, so I'm stuck still
 
Liquidxlax said:
what about the d^2? It has no known value, so I'm stuck still

Start with the linear equations you got from differentiating. They are the easier ones. Save the quadratic for last.
 
thanks for the help i did manage to solve it :D
 

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