What Are the Correct Partial Derivatives of the Function f(x, y) = x√(xy)?

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SUMMARY

The discussion focuses on the correct computation of partial derivatives for the function f(x, y) = x√(xy). The established derivatives are fx = (3/2)√(xy), fy = (x√x) / (2√y), fxx = (3√y) / (4√x), fxy = (3√x) / (4√y), fyx = (3√x) / (4√y), and fyy = -(x√x) / (4y√. A participant expresses confusion regarding the calculation of fx and the second derivative fxx, questioning the validity of their own derived expression.

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jmher0403
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Homework Statement



(x,y) = x√(xy)

The answer says:

fx=3/2*√(xy)
fy=(x√x) / (2√y)
fxx= (3√y) / (4√x)
fxy= (3√x) / (4√y)
fyx =(3√x) / (4√y)
fyy = -(x√x) / (4y√

I don't get from the beginning.

shouldnt fx be equal to (3/2)x^2 * (x^3 * y)^-(3/2)??

When I do second derivative fxx from fx, it doesn't still make sense...

please help
 
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Why do you think fx be equal to (3/2)x^2 * (x^3 * y)^-(3/2)??
 

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