Partial Fraction Decomposition: Nominator or Denominator?

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Homework Help Overview

The discussion revolves around the topic of partial fraction decomposition, specifically focusing on whether to analyze the numerator or the denominator of a given expression. Participants are exploring the process of factoring and separating components of rational functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the importance of the denominator in partial fraction decomposition and question how to determine the appropriate form for the numerators based on the types of denominators (linear vs. quadratic).

Discussion Status

There is an ongoing exploration of different forms for the numerators based on the nature of the denominators. Some participants are attempting to clarify their understanding of how to set up the fractions correctly, while others are sharing their interpretations and examples.

Contextual Notes

Participants are navigating through specific examples involving quadratic denominators and expressing uncertainty about the correct forms to use for the numerators in various scenarios.

myusernameis
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Homework Statement



do we look at the nominator or the denominator? are we trying to separate them? factoring them?

thanks
 
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Hi myusernameis! :wink:
myusernameis said:
do we look at the nominator or the denominator? are we trying to separate them? factoring them?

The denominator. And you factor it. :smile:
 
tiny-tim said:
Hi myusernameis! :wink:


The denominator. And you factor it. :smile:

thanks for the answers!

so let's say i have this long equation in denom.

[tex]\frac{1}{(s^2+1)(s^2+4s-12)}[/tex]

i can factor one of them to look like:

[tex]\frac{1}{(s^2+1)(s+6)(s-4)}[/tex]

but then how do I know if I should use A +B or As+B, Cs+D, etc..?
 
myusernameis said:
i can factor one of them to look like:

[tex]\frac{1}{(s^2+1)(s+6)(s-4)}[/tex]

erm :redface: … nooo!
but then how do I know if I should use A +B or As+B, Cs+D, etc..?

sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:
 
tiny-tim said:
erm :redface: … nooo!


sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:


haha made a mistake... so with that, do i use As+ B?

what if it's (s^2+2)(s^2+3)(s^2+5), ie, several s squares?
 
tiny-tim said:
erm :redface: … nooo!


sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:


if was supposed to be a (s+6)(s-2)...
 
myusernameis said:
what if it's (s^2+2)(s^2+3)(s^2+5), ie, several s squares?

each one has a linear top :smile:
myusernameis said:
if was supposed to be a (s+6)(s-2)...

each one has a number on the top
 
tiny-tim said:
each one has a linear top :smile:

ok,

taking this example again: (s^2+2)(s^2+3)(s^2+5)

would it be: 1 = (As+B)/(s^2+2)(s^2+3)(s^2+5) + (Cs+D)/(s^2+2)(s^2+3)(s^2+5) + (Es+F)/(s^2+2)(s^2+3)(s^2+5) ?
 
myusernameis said:
ok,

taking this example again: (s^2+2)(s^2+3)(s^2+5)

would it be: 1 = (As+B)/(s^2+2)(s^2+3)(s^2+5) + (Cs+D)/(s^2+2)(s^2+3)(s^2+5) + (Es+F)/(s^2+2)(s^2+3)(s^2+5) ?

uhh? :confused:

it's 1/(s2+2)(s2+3)(s2+5)

= (As+B)/(s2+2) + (Cs+D)/(s2+3) + (Es+F)/(s2+5)
 
  • #10
tiny-tim said:
uhh? :confused:

it's 1/(s2+2)(s2+3)(s2+5)

= (As+B)/(s2+2) + (Cs+D)/(s2+3) + (Es+F)/(s2+5)

haha brain fart on my part(i hope)


thanks
 
  • #11
myusernameis said:
haha brain fart on my part(i hope)

wow! where's your brain? :biggrin:
 
  • #12
are you a math teacher?
if you don't mind me asking!
 
  • #13
i'm just a little goldfish …

trying to make sense of the bowliverse! :smile:
 
  • #14
tiny-tim said:
i'm just a little goldfish …

trying to make sense of the bowliverse! :smile:

haha! well, thanks for the help!
 

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