Partial Fraction Decomposition: Nominator or Denominator?

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Homework Statement



do we look at the nominator or the denominator? are we trying to separate them? factoring them?

thanks
 
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tiny-tim said:
Hi myusernameis! :wink:


The denominator. And you factor it. :smile:

thanks for the answers!

so let's say i have this long equation in denom.

[tex]\frac{1}{(s^2+1)(s^2+4s-12)}[/tex]

i can factor one of them to look like:

[tex]\frac{1}{(s^2+1)(s+6)(s-4)}[/tex]

but then how do I know if I should use A +B or As+B, Cs+D, etc..?
 
myusernameis said:
i can factor one of them to look like:

[tex]\frac{1}{(s^2+1)(s+6)(s-4)}[/tex]

erm :redface: … nooo!
but then how do I know if I should use A +B or As+B, Cs+D, etc..?

sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:
 
tiny-tim said:
erm :redface: … nooo!


sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:


haha made a mistake... so with that, do i use As+ B?

what if it's (s^2+2)(s^2+3)(s^2+5), ie, several s squares?
 
tiny-tim said:
erm :redface: … nooo!


sorry, not following you …

for a linear denominator, it's just a number on the top,

for a quadratic denominator, it's a linear top :smile:


if was supposed to be a (s+6)(s-2)...
 
myusernameis said:
what if it's (s^2+2)(s^2+3)(s^2+5), ie, several s squares?

each one has a linear top :smile:
myusernameis said:
if was supposed to be a (s+6)(s-2)...

each one has a number on the top
 
tiny-tim said:
each one has a linear top :smile:

ok,

taking this example again: (s^2+2)(s^2+3)(s^2+5)

would it be: 1 = (As+B)/(s^2+2)(s^2+3)(s^2+5) + (Cs+D)/(s^2+2)(s^2+3)(s^2+5) + (Es+F)/(s^2+2)(s^2+3)(s^2+5) ?
 
myusernameis said:
ok,

taking this example again: (s^2+2)(s^2+3)(s^2+5)

would it be: 1 = (As+B)/(s^2+2)(s^2+3)(s^2+5) + (Cs+D)/(s^2+2)(s^2+3)(s^2+5) + (Es+F)/(s^2+2)(s^2+3)(s^2+5) ?

uhh? :confused:

it's 1/(s2+2)(s2+3)(s2+5)

= (As+B)/(s2+2) + (Cs+D)/(s2+3) + (Es+F)/(s2+5)
 
tiny-tim said:
uhh? :confused:

it's 1/(s2+2)(s2+3)(s2+5)

= (As+B)/(s2+2) + (Cs+D)/(s2+3) + (Es+F)/(s2+5)

haha brain fart on my part(i hope)


thanks
 
are you a math teacher?
if you don't mind me asking!
 
tiny-tim said:
i'm just a little goldfish …

trying to make sense of the bowliverse! :smile:

haha! well, thanks for the help!