Partial Fraction Expansion for Denominator Coefficients

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Homework Help Overview

The discussion revolves around the topic of partial fraction expansion (PFE) in the context of inverse Laplace transforms. Participants are exploring whether denominators in PFE can have coefficients other than one, using specific examples to illustrate their points.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the necessity of having coefficients equal to one in the denominator for PFE. They provide examples and seek clarification on whether it is acceptable to leave coefficients as they are or if they should be factored out.

Discussion Status

Some participants have offered guidance suggesting that it is possible to work with coefficients other than one, while others are exploring the implications of factoring out coefficients in their setups. There is an ongoing examination of different setups and their correctness.

Contextual Notes

Participants mention that their inquiries are related to the process of taking the inverse Laplace transform, indicating a specific application context for their questions. There is also a reference to previous experiences with the topic, suggesting varying levels of familiarity among participants.

btbam91
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For PFE, can a denominator variables with coefficient of something other than 1, or does it have to be 1?

For Example, can I have a term A/(3x+9)?

It's been years since I've dealt with this and don't quite remember if this was a rule or not.

Thanks!

EDIT: This is in terms of taking the inverse laplace transform later.
 
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Just to put things into perspective, is the first image ok or do I have to follow what I did in the second image?
 

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btbam91 said:
For PFE, can a denominator variables with coefficient of something other than 1, or does it have to be 1?

For Example, can I have a term A/(3x+9)?

It's been years since I've dealt with this and don't quite remember if this was a rule or not.

Thanks!

EDIT: This is in terms of taking the inverse Laplace transform later.

You can do it either way. But why would you not factor out the 3?

attachment.php?attachmentid=50620&d=1347238675.png


attachment.php?attachmentid=50621&d=1347238675.png
 
It's just been a while since I've done these. For some reason I thought it was a rule that the coefficients had to be 1 or something.

In my 2nd image, is it set up correctly? Where the 3 remains on the left but the K1/s should not be K1/3s?
 
btbam91 said:
In my 2nd image, is it set up correctly? Where the 3 remains on the left but the K1/s should not be K1/3s?

Oh, I missed that.

To find the coefficients the second way, you should include the 1/3 as follows.
[itex]\displaystyle \frac{5}{s(3s^2+30s+63)}=<br /> \frac{1}{3}\left(\frac{k_1}{s}+\frac{k_2}{s+3}+ \frac{k_3}{s+7}\right)[/itex]​
 

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