- #1
snowJT
- 117
- 0
if you have
[tex]\frac{3s + 1}{(s+2)^2 + 4^2}[/tex]
does it become...
[tex]3s + 1 = \frac{A}{(s+2)} + \frac{B}{(s+2)^2} + \frac{C}{4} + \frac{D}{4^2}[/tex]
or...
[tex]3s + 1 = \frac{A}{(s+2)} + \frac{B}{(s+2)^2} + \frac{C}{4^2}[/tex]
[tex]\frac{3s + 1}{(s+2)^2 + 4^2}[/tex]
does it become...
[tex]3s + 1 = \frac{A}{(s+2)} + \frac{B}{(s+2)^2} + \frac{C}{4} + \frac{D}{4^2}[/tex]
or...
[tex]3s + 1 = \frac{A}{(s+2)} + \frac{B}{(s+2)^2} + \frac{C}{4^2}[/tex]