Particle flow in wires of same current but diff diameter?

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Homework Help Overview

The discussion revolves around the flow of electric current in wires of different diameters, specifically addressing how current, resistance, and voltage relate to each other in this context. Participants explore the implications of having the same current in wires with varying cross-sectional areas.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between current, resistance, and voltage, questioning how these factors interact when wire diameters differ. Some express confusion about the implications of constant current in wires with different resistances and cross-sectional areas.

Discussion Status

The conversation is ongoing, with participants offering insights into the relationship between wire diameter, charge flow, and particle velocity. There is recognition of the complexity of the concepts involved, and while some participants suggest that the answer is D, there is no explicit consensus on the reasoning behind it.

Contextual Notes

Some participants note that the definitions and assumptions about current and resistance may need further exploration, particularly regarding how voltage compensates for changes in resistance in wires of different diameters.

toforfiltum
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Homework Statement


upload_2015-7-23_23-20-45.png


Homework Equations


I=Q/t

The Attempt at a Solution


I chose B because since current is equal in both wires, I thought that the rate of charge flow is equal. Isn't that the definition of current?? Apparently I'm wrong since the answer is D. How can this be?
 
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the resistance of a wire depends on it's cross section. the smaller the cross section, the higher the resistance. if the resistance is higher, you need a higher voltage to produce the same current. that's why the answer is D...none of these answers are really satisfactory...
 
cpsinkule said:
the resistance of a wire depends on it's cross section. the smaller the cross section, the higher the resistance. if the resistance is higher, you need a higher voltage to produce the same current. that's why the answer is D...none of these answers are really satisfactory...
But won't the higher voltage be offset by the higher resistance, since I=V/R?
 
the current is the same in both wires, if the resistance goes up, the only way for that equation to remain true is if the voltage goes up as well
 
cpsinkule said:
the current is the same in both wires, if the resistance goes up, the only way for that equation to remain true is if the voltage goes up as well
So does that mean that the charged particles will move faster through the wire?
 
yes, the net amount of charge passing through one point in the wires is proportional to the area of the wire and the speed of the electrons. both of these have equal current so that a smaller area requires a larger velocity to produce the same current
 
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Maybe D is the correct answer, but it's a weird way of thinking.

Instead think of an hourglass whre sand is flowing through a narrow hole. Where in the hourglass will the sand flow fastest? At the biggest/smallest cross section area?
And why?
 
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cpsinkule said:
yes, the net amount of charge passing through one point in the wires is proportional to the area of the wire and the speed of the electrons. both of these have equal current so that a smaller area requires a larger velocity to produce the same current
Ah, I see, so to confirm, to produce the same amount of charge flowing through a smaller cross-sectional area per unit time, the velocity of the particles must be higher, right?
 
that's the idea
 
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Hesch said:
Maybe D is the correct answer, but it's a weird way of thinking.

Instead think of an hourglass whre sand is flowing through a narrow hole. Where in the hourglass will the sand flow fastest? At the biggest/smallest cross section area?
And why?
Wow, nice question, though I'm not sure about the answer.:biggrin: I suppose it should be at the smallest cross-sectional area, since it's at point of lowest pressure? Add also, rate of flow must be equal everywhere, so to make up for the smaller cross-sectional area, the sand there must flow faster...but what I say seems contradictory...
 

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