1. The problem statement, all variables and given/known data Not exactly sure why a time value of 0.500s is given, but I am positive it is why my answer isn't correct: Q. a 1kg object is attached to a horizontal spring. The spring is initially stretched by 0.100m and the object is released from rest there. It proceeds to move without friction. The next time the speed of the object is zero is 0.500s later. What is the maximum speed of the object? 2. Relevant equations Vmax = Aω ω=√(k/m) Fs=-kx 3. The attempt at a solution Given: t = 0.5s Amplitude: 0.100m m: 1kg I can find k: Fs=-kx mg = -kx (1kg * -9.8) = -k (0.100m) k = 98 N/m Find ω ω=√(k/m) = √(98/1) = 9.90 Vmax = Aω =(0.1)(9.90) =0.990 m/s. However, the answer is 0.628m/s. I don't understand the purpose of "the next time the velocity is zero is 0.5s later" I interpret that as: "it to 0.5seconds to reach negative amplitude", which to my understanding isn't needed?